]> https://gitweb.dealii.org/ - dealii-svn.git/commitdiff
One final note
authorbangerth <bangerth@0785d39b-7218-0410-832d-ea1e28bc413d>
Wed, 6 Sep 2006 23:26:33 +0000 (23:26 +0000)
committerbangerth <bangerth@0785d39b-7218-0410-832d-ea1e28bc413d>
Wed, 6 Sep 2006 23:26:33 +0000 (23:26 +0000)
git-svn-id: https://svn.dealii.org/trunk@13848 0785d39b-7218-0410-832d-ea1e28bc413d

deal.II/examples/step-23/doc/intro.dox

index 7dda1b6864592c5b173d3781384d46a20e028b35..bfb31d8df4090000c19b80b4cbb8fe93d5d03974 100644 (file)
@@ -294,7 +294,11 @@ It is worth noting that if we choose the same mesh on each time step
 (as we will in fact do in the program below), then we have the same
 shape functions on time step $n$ and $n-1$,
 i.e. $\phi^n_i=\phi_i^{n-1}=\phi_i$. Consequently, we get
-$M^n=M^{n,n-1}=M$ and $A^n=A^{n,n-1}=A$.
+$M^n=M^{n,n-1}=M$ and $A^n=A^{n,n-1}=A$. On the other hand, if we had
+used different shape functions, then we would have to compute
+integrals that contain shape functions defined on two meshes. This is a
+somewhat messy process that we omit here, but that is treated in some
+detail in @ref step_22 "step-22".
 
 As a final note, we remember that we have posed boundary values for
 $u$, but not $v$. In practice that means that we have to apply

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