From: bangerth <bangerth@0785d39b-7218-0410-832d-ea1e28bc413d>
Date: Thu, 24 Jun 2010 01:42:12 +0000 (+0000)
Subject: Fix mathematical description.
X-Git-Url: https://gitweb.dealii.org/cgi-bin/gitweb.cgi?a=commitdiff_plain;h=8345795e320967c93e857a777c4204cce7b7a776;p=dealii-svn.git

Fix mathematical description.


git-svn-id: https://svn.dealii.org/trunk@21305 0785d39b-7218-0410-832d-ea1e28bc413d
---

diff --git a/deal.II/examples/step-45/doc/intro.dox b/deal.II/examples/step-45/doc/intro.dox
index 92e860f95f..06415e6554 100644
--- a/deal.II/examples/step-45/doc/intro.dox
+++ b/deal.II/examples/step-45/doc/intro.dox
@@ -32,11 +32,12 @@ consider the problem
    -\Delta u &=
    \pi^2\sin(\pi x)\sin(\pi y)  \qquad &\text{in }\Omega
   \\ 
-   u(0,y) &= 0 \qquad &\text{for }y\in(0,1)
+   u(x,0) &= 0 \qquad &\text{for }x\in(0,1)\qquad &&\text{(bottom boundary)}
   \\
-   u(1,y) &= 0 \qquad &\text{for }y\in(0,1)
+   u(x,1) &= 0 \qquad &\text{for }x\in(0,1)\qquad &&\text{(top boundary)}
   \\
-   u(x,0) &= u(x,1) \qquad &\text{for }x\in(0,1) 
+   u(0,y) &= u(1,y) \qquad &\text{for }y\in(0,1) 
+   \qquad && \text{(left and right boundaries)}
 @f}
 
 The way one has to see these periodic boundary conditions $u(x,0) = u(x,1)$ is