From: Wolfgang Bangerth Date: Wed, 4 Mar 2020 01:23:58 +0000 (-0700) Subject: Use \mathbf C to denote the stress-strain tensor. X-Git-Tag: v9.2.0-rc1~466^2 X-Git-Url: https://gitweb.dealii.org/cgi-bin/gitweb.cgi?a=commitdiff_plain;h=refs%2Fpull%2F9601%2Fhead;p=dealii.git Use \mathbf C to denote the stress-strain tensor. --- diff --git a/examples/step-8/doc/intro.dox b/examples/step-8/doc/intro.dox index 6d1f929394..f6c9085163 100644 --- a/examples/step-8/doc/intro.dox +++ b/examples/step-8/doc/intro.dox @@ -26,16 +26,16 @@ as @f[ - \text{div}\, - (C \nabla \mathbf{u}) + ({\mathbf C} \nabla \mathbf{u}) = \mathbf f, @f] where $\mathbf u$ is the vector-valued displacement at each point, -$\mathbf f$ the force, and $C$ is a rank-4 tensor (i.e., it has four +$\mathbf f$ the force, and ${\mathbf C}$ is a rank-4 tensor (i.e., it has four indices) that encodes the stress-strain relationship -- in essence, it represents the "spring constant" in -Hookes law that relates the displacement to the forces. $C$ will, in many +Hookes law that relates the displacement to the forces. ${\mathbf C}$ will, in many cases, depend on $\mathbf x$ if the body whose deformation we want to simulate is composed of different materials. @@ -57,15 +57,15 @@ then read as @f[ - \text{div}\, - (C \varepsilon(\mathbf u)) + ({\mathbf C} \varepsilon(\mathbf u)) = \mathbf f, @f] which you can think of as the more natural generalization of the Laplace equation to vector-valued problems. (The form shown first is equivalent to -this form because the tensor $C$ has certain symmetries, namely that -$C_{ijkl}=C_{ijlk}$, and consequently $C \varepsilon(\mathbf u)_{kl} -= C \nabla\mathbf u$.) +this form because the tensor ${\mathbf C}$ has certain symmetries, namely that +$C_{ijkl}=C_{ijlk}$, and consequently ${\mathbf C} \varepsilon(\mathbf u)_{kl} += {\mathbf C} \nabla\mathbf u$.) One can of course alternatively write these equations in component form: @f[