From 11d9c66a88e1f2549f5ac4aa30b3cf0e416260be Mon Sep 17 00:00:00 2001
From: bonito <bonito@0785d39b-7218-0410-832d-ea1e28bc413d>
Date: Wed, 5 Jan 2011 20:56:29 +0000
Subject: [PATCH] git-svn-id: https://svn.dealii.org/trunk@23129
 0785d39b-7218-0410-832d-ea1e28bc413d

---
 deal.II/examples/step-38/doc/intro.dox | 12 ++++++------
 1 file changed, 6 insertions(+), 6 deletions(-)

diff --git a/deal.II/examples/step-38/doc/intro.dox b/deal.II/examples/step-38/doc/intro.dox
index ebdcdf889a..034de548e2 100644
--- a/deal.II/examples/step-38/doc/intro.dox
+++ b/deal.II/examples/step-38/doc/intro.dox
@@ -41,7 +41,7 @@ constituted of quadrilaterals.
 We are now in position to define the tangential gradient of a function $v : S \rightarrow \mathbb
 R$ by
 @f[
-(\nabla_S v)\circ \mathbf x_S :=  D \mathbf x_S \ G_S^{-1} \ D (v \circ \mathbf x_S).
+(\nabla_S v)\circ \mathbf x_S :=  D \mathbf x_S \ G_S^{-1} \ \nabla (v \circ \mathbf x_S).
 @f]
 The surface Laplacian (also called the Laplace-Beltrami operator) is then
 defined as  $\Delta_S:= \nabla_S \cdot \nabla_S$.
@@ -66,7 +66,7 @@ solutions). We therefore resort to the weak formulation
 @f]
 and take advantage of the partition ${\mathbb T}$ to further write
 @f[
-\sum_{K\in  {\mathbb T}}\int_K \nabla_K u \cdot \nabla_K v = \sum_{K\in
+\sum_{K\in  {\mathbb T}}\int_K \nabla_{K} u \cdot \nabla_{K} v = \sum_{K\in
   {\mathbb T}} \int_K f \ v  \qquad \forall v \in H^1_0(\Gamma).
 @f]
 Moreover, each integral in the above expression is computed in the reference
@@ -75,12 +75,12 @@ so that
 @f{align*}
 &\int_{K} \nabla_{K} u \cdot \nabla_{K} v \\
 &= 
-\int_{\hat K} D(u \circ \mathbf x_K)^T G_K^{-1} (D \mathbf
-  x_K)^T D \mathbf x_K G_K^{-1} D(v \circ \mathbf x_K) \sqrt{\det
+\int_{\hat K} \nabla (u \circ \mathbf x_K)^T G_K^{-1} (D \mathbf
+  x_K)^T D \mathbf x_K G_K^{-1} \nabla(v \circ \mathbf x_K) \sqrt{\det
     (G_K)}
 \\
 &= 
-\int_{\hat K} D(u \circ \mathbf x_K)^T G_K^{-1} D(v \circ \mathbf x_K) \sqrt{\det
+\int_{\hat K} \nabla (u \circ \mathbf x_K)^T G_K^{-1} \nabla (v \circ \mathbf x_K) \sqrt{\det
     (G_K)}
 @f}
 and
@@ -94,7 +94,7 @@ Finally, we use a quadrature formula defined by points $\{p_l\}_{l=1}^N\subset
 evaluate the above integrals and
 obtain
 @f[\int_{K} \nabla_{K} u \cdot \nabla_{K} v \approx \sum_{l=1}^N
- (D(u \circ \mathbf x_K)(p_l))^T G^{-1}(p_l)  D(v \circ \mathbf x_K)
+ (\nabla (u \circ \mathbf x_K)(p_l))^T G^{-1}(p_l)  \nabla (v \circ \mathbf x_K)
 (p_l) \sqrt{\det (G(p_l))} \ w_l
 @f]
 and
-- 
2.39.5