From b5182d23a2b0b47a160765084bba55c257d5ea38 Mon Sep 17 00:00:00 2001
From: turcksin <turcksin@0785d39b-7218-0410-832d-ea1e28bc413d>
Date: Fri, 16 May 2014 19:04:54 +0000
Subject: [PATCH] Fix typos in the documentation of step-52.

git-svn-id: https://svn.dealii.org/trunk@32927 0785d39b-7218-0410-832d-ea1e28bc413d
---
 deal.II/examples/step-52/doc/intro.dox | 6 +++---
 deal.II/examples/step-52/step-52.cc    | 8 ++++----
 2 files changed, 7 insertions(+), 7 deletions(-)

diff --git a/deal.II/examples/step-52/doc/intro.dox b/deal.II/examples/step-52/doc/intro.dox
index 4ae88a593d..11d19584c0 100644
--- a/deal.II/examples/step-52/doc/intro.dox
+++ b/deal.II/examples/step-52/doc/intro.dox
@@ -8,7 +8,7 @@
 This program shows how to use Runge-Kutta methods to solve a time-dependent
 problem.
 
-<h3>Problem statement<h3>
+<h3>Problem statement</h3>
 
 In this example, we solve the energy-integrated time-dependent diffusion
 approximation of the neutron transport equation (see step-28 for the
@@ -36,7 +36,7 @@ S=A\left(\frac{1}{v}\omega \cos(\omega t)(bx -x^2) + \sin(\omega t)
 \left(\Sigma_a (bx-x^2)+2D\right) \right).
 @f}
 Because the solution is a sine, we know that
-\f$\phi\left(x,\frac{\pi}{\omega}\right) = 0$. Therefore, we can easily
+$\phi\left(x,\frac{\pi}{\omega}\right) = 0$. Therefore, we can easily
 compute the error at this time since it is simply the norm of the solution
 found.
 
@@ -74,7 +74,7 @@ categories:
 
 <h4>Explicit Runge-Kutta</h4>
 These methods that include for forward Euler, third order Runge-Kutta, and
-fourth order Runge-Kutta, require a function to evaluate $M^{-1}f(t,y). These
+fourth order Runge-Kutta, require a function to evaluate $M^{-1}f(t,y)$. These
 methods become unstable when the time step chosen is too large.
 
 <h4>Embedded Runge-Kutta</h4>
diff --git a/deal.II/examples/step-52/step-52.cc b/deal.II/examples/step-52/step-52.cc
index 1031e49cdd..f13222ed70 100644
--- a/deal.II/examples/step-52/step-52.cc
+++ b/deal.II/examples/step-52/step-52.cc
@@ -83,11 +83,11 @@ namespace Step52
       // Compute the intensity of the source at the given point.
       double get_source(double time,const Point<2> &point) const;
       
-      // Evaluate the diffusion equation \f$M^{-1}(f(t,y))\f$
+      // Evaluate the diffusion equation $M^{-1}(f(t,y))$
       Vector<double> evaluate_diffusion(const double time, const Vector<double> &y) const;
 
-      // Evaluate \f$\left(I-\tau M^{-1} \frac{\partial f(t,y)}{\partial y}\right)^{-1} = 
-      // \left(M-\tau \frac{\partial f}{\partial y}\right)^{-1} M \f$
+      // Evaluate $\left(I-\tau M^{-1} \frac{\partial f(t,y)}{\partial y}\right)^{-1} = 
+      // \left(M-\tau \frac{\partial f}{\partial y}\right)^{-1} M $
       Vector<double> id_minus_tau_J_inverse(const double time, const double tau, 
           const Vector<double> &y);
       
@@ -196,7 +196,7 @@ namespace Step52
     cell = dof_handler.begin_active(),
     endc = dof_handler.end();
            
-    // Compute \f$-\int D \nabla b \cdot \nabla b - \int \Sigma_a b b\f$ and \f$\int b b\f$
+    // Compute $-\int D \nabla b \cdot \nabla b - \int \Sigma_a b b $ and $\int b b $
     for (; cell!=endc; ++cell)
     {
       cell_matrix = 0.;
-- 
2.39.5