From b26899db3894511cb5e58c09a2a12c687ae84e41 Mon Sep 17 00:00:00 2001 From: David Wells Date: Mon, 11 May 2020 10:17:28 -0400 Subject: [PATCH] Fix some small things in step-44's introduction. --- examples/step-44/doc/intro.dox | 4 ++-- 1 file changed, 2 insertions(+), 2 deletions(-) diff --git a/examples/step-44/doc/intro.dox b/examples/step-44/doc/intro.dox index a105f1faef..bb8946b3d7 100644 --- a/examples/step-44/doc/intro.dox +++ b/examples/step-44/doc/intro.dox @@ -116,7 +116,7 @@ The fourth-order SymmetricTensor returned by identity_tensor() is $ Let the time domain be denoted $\mathbb{T} = [0,T_{\textrm{end}}]$, where $t \in \mathbb{T}$ and $T_{\textrm{end}}$ is the total problem duration. Consider a continuum body that occupies the reference configuration $\Omega_0$ at time $t=0$. -Particles in the reference configuration are identified by the position vector $\mathbf{X}$. +%Particles in the reference configuration are identified by the position vector $\mathbf{X}$. The configuration of the body at a later time $t>0$ is termed the current configuration, denoted $\Omega$, with particles identified by the vector $\mathbf{x}$. The nonlinear map between the reference and current configurations, denoted $\boldsymbol{\varphi}$, acts as follows: @f[ @@ -276,7 +276,7 @@ The fictitious Kirchhoff stress tensor $\overline{\boldsymbol{\tau}}$ is defined pressure in solid mechanics as $p = - 1/3 \textrm{tr} \boldsymbol{\sigma} = - 1/3 J^{-1} \textrm{tr} \boldsymbol{\tau}$. Here $p$ is the hydrostatic pressure. -We make use of the pressure response throughout this tut (although we refer to it as the pressure). +We make use of the pressure response throughout this tutorial (although we refer to it as the pressure).

Neo-Hookean materials

-- 2.39.5