From 0a6183226bef510b24daf21790acd481eaa7a09d Mon Sep 17 00:00:00 2001 From: Lei Qiao Date: Sat, 5 Sep 2015 14:45:29 -0500 Subject: [PATCH] correct equation in intro of step-15 --- examples/step-15/doc/intro.dox | 4 ++-- 1 file changed, 2 insertions(+), 2 deletions(-) diff --git a/examples/step-15/doc/intro.dox b/examples/step-15/doc/intro.dox index 5f103cafa6..b2e777b1a4 100644 --- a/examples/step-15/doc/intro.dox +++ b/examples/step-15/doc/intro.dox @@ -112,7 +112,7 @@ Reducing this space to a finite dimensional space with basis $\left\{ \varphi_{0},\dots , \varphi_{N-1}\right\}$, we can write the solution: @f[ - \delta u^{n}=\sum_{j=0}^{N-1} U_{j} \varphi_{j}. + \delta u^{n}=\sum_{j=0}^{N-1} \delta U_{j} \varphi_{j}. @f] Using the basis functions as test functions and defining $a_{n}:=\frac{1} @@ -121,7 +121,7 @@ Using the basis functions as test functions and defining $a_{n}:=\frac{1} @f[ \sum_{j=0}^{N-1}\left[ \left( \nabla \varphi_{i} , a_{n} \nabla \varphi_{j} \right) - \left(\nabla u^{n}\cdot \nabla \varphi_{i} , a_{n}^{3} \nabla u^{n} \cdot \nabla - \varphi_{j} \right) \right] \cdot U_{j}=\left( \nabla \varphi_{i} , a_{n} + \varphi_{j} \right) \right] \cdot \delta U_{j}=\left( \nabla \varphi_{i} , a_{n} \nabla u^{n}\right) \qquad \forall i=0,\dots ,N-1, @f] -- 2.39.5